Dear Charles.
To make sure that I now understand look at my diagram.2 The two
A, F in the hexagon the section of the Dodec.
Call CB radius of sphere (r) & CF radius of ⊙ in which the hexagon is inscribed r′, then
| r′ : r :: .8165 : 1 | ||
| in the bees hexagon | r′ = 0inch.125 or ⅛ inch | |
| .:. | r = = = 0inch.153 | |
| r−r′ = 0inch.028 distance sought. | ||
| The distance from center to obtuse ∠ | ||
| = r .866 = 0in.153 ×.866 = 0in.1325 | ||
| distance to ob: ∠ of Dodec | = 0.1325 | |
| r′ = distance to ∠ of Heg | = 0.1250 | |
| Difference = | 0.0075 | |
| or ¾ of inch. | ||
Make no scruple of asking any number of explanations, as it is very little trouble to me, & saves you bother.3
Yours E D
| CB = R = 1 |
|
|
| CC’= R = 1.414 | ||
| EF = FG = side of hexagon | ||
| EF = EC × tang 30o = EC × | ||
| EC = | ||
| 2EF = FG = = .8165 | ||
|
||
Please cite as “DCP-LETT-2278,” in Ɛpsilon: The Charles Darwin Collection accessed on