15 November 1821
From a careful analysis of 5 grains of Mr. Henslow’s mineral from Anglesea, independently of its crystalline form, it appears to consist of
Gr
Silica, 3 = 60
Alumina, 1 1/10 = 22
Soda, 5/10 = 10
Lime, 1/10 = 2
Water of absorption 1/10 = 2
Loss, Zn 2 Iron 2
Grains — 4/100
Total 4. 8/10
without the Loss
w.ch equals 2/10
This Mineral gelatinizes in acid & is electric by friction. It is properly therefore anhydrous analcine, & quite a new variety.
E.D.Clarke
Please cite as “HENSLOW-2,” in Ɛpsilon: The Correspondence of John Stevens Henslow accessed on 19 April 2024, https://epsilon.ac.uk/view/henslow/letters/letters_2